Bài 1 viết các đa thức sau dưới dạng 1 tích a, A=x^3 125 b, B= 8y^2-1 c. C=64x^3 27 Bài 2 rút gọn các biểu thức sau a, (x 2)(x^2-2x 4)-(x^2-4) b, B=(a 2)(a-2)(a^2 2a 4)(a^2-2a 4) Bài 3 Tính gi...

Hãy tham gia nhóm Học sinh Hoc24OLM

Lê Hoàng 13 tháng 7 2017 lúc 22:53

Bài 1 viết các đa thức sau dưới dạng 1 tích a, Ax^3 +125 b, B 8y^2-1 c. C64x^3+27 Bài 2 rút gọn các biểu thức sau a, (x+2)(x^2-2x+4)-(x^2-4) b, B(a+2)(a-2)(a^2+2a+4)(a^2-2a+4) Bài 3 Tính giá trị biểu thức sau a, A x^2 +4x+4 tại x198 b, B(2x-1)^2+(2x+1)^2+2(4x^2-1) với x1/4 c, C(x-1)^3-(x-1)(x^2+x+1+3)(x-1)(x+1) với x1/3 Giups mk với cảm ơn các bạn nhìu

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Bài 1 viết các đa thức sau dưới dạng 1 tích

a, A=x^3 +125

b, B= 8y^2-1

c. C=64x^3+27

Bài 2 rút gọn các biểu thức sau

a, (x+2)(x^2-2x+4)-(x^2-4)

b, B=(a+2)(a-2)(a^2+2a+4)(a^2-2a+4)

Bài 3 Tính giá trị biểu thức sau

a, A =x^2 +4x+4 tại x=198

b, B=(2x-1)^2+(2x+1)^2+2(4x^2-1) với x=1/4

c, C=(x-1)^3-(x-1)(x^2+x+1+3)(x-1)(x+1) với x=1/3

Giups mk với cảm ơn các bạn nhìu

Lớp 8 Toán Bài 3: Những hằng đẳng thức đáng nhớ

Bẻo Phương

20 tháng 8 2021 lúc 20:16

Bài 2: Viết các biểu thức sau dưới dạng bình phương một tổng a) x² + 6x + 9 b) x² + x + 1 Bài 3: Rút gọn biểu thức: a) (x +y)2+(x - y) Bài 4: Tìm x biết a) (2x + 1)²- 4(x + 2)²9 b) (x+3)²-(x-4)( x + 8) 1 Bài 5: Tính nhẩm: a) 19. 21 b) 29.31 c) 2xy² + x²y + 1 b)2(x - y)(x + y) +(x - y)²+ (x + y)² c) 3(x + 2)²+ (2x - 1)²- 7(x + 3)(x - 3) 36 c) 39. 41: Bài 6: Chứng minh rằng các biểu thức sau luôn dương với mọi giá trị của biển x a) 9x² - 6x +2 b) x² + x + 1 Bài 7: Tìm GTNN của: a)A...

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Bài 2: Viết các biểu thức sau dưới dạng bình phương một tổng a) x² + 6x + 9 b) x² + x + 1 Bài 3: Rút gọn biểu thức: a) (x +y)2+(x - y) Bài 4: Tìm x biết a) (2x + 1)²- 4(x + 2)²=9 b) (x+3)²-(x-4)( x + 8) = 1 Bài 5: Tính nhẩm: a) 19. 21 b) 29.31 c) 2xy² + x²y + 1 b)2(x - y)(x + y) +(x - y)²+ (x + y)² c) 3(x + 2)²+ (2x - 1)²- 7(x + 3)(x - 3) = 36 c) 39. 41: Bài 6: Chứng minh rằng các biểu thức sau luôn dương với mọi giá trị của biển x a) 9x² - 6x +2 b) x² + x + 1 Bài 7: Tìm GTNN của: a)A=x-3x+5 Bài 8: Tìm GTLNcủa: a) A = 4 - x² + 2x Bài 9: Tính giá trị của biểu thức A = x³+ 12x²+ 48x + 64 tai x = 6 C=x+9x+27x + 27 tại x= - 103 c) 2x² + 2x + 1. b) B = (2x - 1)² + (x + 2)² b) B = 4x - x² B=x −6x + 12x – 8 tại x = 22 D=x³15x² + 75x - 125 tai x = 25 Bài 10.Tìm x biết: a) (x - 3)(x + 3x +9)+x(x + 2)2 - x)=1 b)(x+1)- (x - 1) - 6(x - 1}} = Bài 11: Rút gọn: a) (x - 2) - x(x + 1)(x - 1) + 6x(x - 3) b)(x - 2)(x - 2x+4)(x+2)(x+2x+

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Lớp 8 Toán Violympic toán 8

Nguyễn Lê Phước Thịnh CTV

20 tháng 8 2021 lúc 20:26

Bài 8:

Ta có: \(A=-x^2+2x+4\)

\(=-\left(x^2-2x-4\right)\)

\(=-\left(x^2-2x+1-5\right)\)

\(=-\left(x-1\right)^2+5\le5\forall x\)

Dấu '=' xảy ra khi x=1

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Nguyễn Thị Kim Chi

18 tháng 7 2016 lúc 13:09

Bài 1 : Viết các đa thức sau dưới dạng tích :a. 1/64x^3 -1b. x^6- y^3c.27x3-8y^3d.8x^3+125x^3Bài 2 : Rút gọna. (a+b)^3 + (1 -b)^3 - 6a^2bb.(a+b)^3 - (a-b)^3 - 6a^2bBài 3 : TínhA x^3 +15x^2 + 75x + 125 tại x -1B x^3 - 9x^2 + 27x - 27 tại x 13C x^3/8 + xy^2/6 + y^3/27 . c -8, y6Cảm ơn bạn nào giúp mình nhiều nhaaaMình cần gấp nên bạn nào giải được giải nhanh dùm mình :(( Cảm ơn ạ

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Bài 1 : Viết các đa thức sau dưới dạng tích :

a. 1/64x^3 -1
b. x^6- y^3

c.27x3-8y^3

d.8x^3+125x^3

Bài 2 : Rút gọn
a. (a+b)^3 + (1 -b)^3 - 6a^2b

b.(a+b)^3 - (a-b)^3 - 6a^2b
Bài 3 : Tính

A = x^3 +15x^2 + 75x + 125 tại x = -1

B = x^3 - 9x^2 + 27x - 27 tại x =13

C = x^3/8 + xy^2/6 + y^3/27 . c= -8, y=6

Cảm ơn bạn nào giúp mình nhiều nhaaa

Mình cần gấp nên bạn nào giải được giải nhanh dùm mình :(( Cảm ơn ạ

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Lớp 8 Toán Câu hỏi của OLM

Tran khanh Linh

20 tháng 12 2016 lúc 15:03

n *o biets

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Nguyễn Trịnh Hoài Thu

4 tháng 8 2016 lúc 18:18

Bài 1 : Dùng hẳng thức triển khai các tích sau : a ) ( 2x - 3y )*(2x+3y)b ) ( 1+5a)*(1+5a)c ) (2a+3b)*(2a+3b)d) ( a+b+c)*(a+b+c) e ) ( x+y-1)*(x-y-1)Bài 2 : Rút gọn rồi tính giá trị của biểu thức :1. M ( 2x+y)^2-(2x+y)*(2x-y)*y*(x-y)với x-2 ; y32. N ( a-3b)^2-(a+3b)^2-(a-1)*(b-2) với a1/2;b-33. P (2x-5)*(2x+5)-(2x+1)^2 với x -2005 4. Q ( y-3)*(y+3)*(y^2+9)-(y^2+2)*(y^2-2) với y 2013^2014Bài 3 : Tìm x , biết :a ) ( x-2)^2 -(x+3)^2-4*(x+1)5b) ( 2x-3)*(2x+3)-(x-1)^2-3x*(x-5)-44c ) (5x+1)^2-(5x...

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Bài 1 : Dùng hẳng thức triển khai các tích sau :

a ) ( 2x - 3y )*(2x+3y)

b ) ( 1+5a)*(1+5a)

c ) (2a+3b)*(2a+3b)

d) ( a+b+c)*(a+b+c)

e ) ( x+y-1)*(x-y-1)

Bài 2 : Rút gọn rồi tính giá trị của biểu thức :

1. M = ( 2x+y)^2-(2x+y)*(2x-y)*y*(x-y)với x=-2 ; y=3

2. N = ( a-3b)^2-(a+3b)^2-(a-1)*(b-2) với a=1/2;b=-3

3. P = (2x-5)*(2x+5)-(2x+1)^2 với x= -2005

4. Q = ( y-3)*(y+3)*(y^2+9)-(y^2+2)*(y^2-2) với y = 2013^2014

Bài 3 : Tìm x , biết :

a ) ( x-2)^2 -(x+3)^2-4*(x+1)=5

b) ( 2x-3)*(2x+3)-(x-1)^2-3x*(x-5)=-44

c ) (5x+1)^2-(5x+3)*(5x+3)=30

d) ( x+3 )^2+(x-2)*(x+2)-2*(x-1)^2=7

Bài 4 : So sánh :

a ) A = 2005*2007 và B = 2006^2

b ) (2+1)*(2^2+1)*(2^4+1)*(2^8+1) và D = 2^32

c ) ( 3+1)*(3^2+1)*(3^4+1)*(3^16+1)=3^32-1

Bài 5 : Tính nhanh :

1 ) 127^2+146*127+73^2

2) 9^8*2^8-(18^4+1)

3) 100^2 -99^3 +98^2-97^2+....+2^2-1^2

4 ) 180^2-220^2/125^2+150*125+75^2

5 ) ( 20^2 +18^2+16^2+....+4^2+2^2 ) -( 19^2+17^2+...+3^2+1^2 )

_____________________________________________________________________________

BÀI TẬP BỔ SUNG

Bài 1 : CM các BT sau có giá trị không âm

A = x^2-4x+9

B= 4x^2+4x+2007

C= 9-6x+x^2

D= 1-x+x^2

Bài 2 :

a . Cho a>b>0 ; 3a^2+3b^2 = 10ab . Tính P=a-b/a+b

b. Cho a>b>0 ; 2a^2+2b^2=5ab .Tính E= a+b/a-b

Bài 3 : Cho biểu thức : A = ( x-2)^2-(x+5)*(x-5)

a ) Rút gọn A

b) Tìm x để A = 1

c ) Tính giá trị của biểu thức A tại -3/4

Bài 6 :

a ) Tính nhanh : 2006^2-36

b ) CMR biểu thức sau có giá trị không âm :

1 . B= x^2-x+1

2. C = 2x^2 +y^2-2xy-10x+27

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Lớp 8 Toán Ôn tập toán 8

Isolde Moria

4 tháng 8 2016 lúc 18:18

ngất

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Lê Nguyên Hạo

4 tháng 8 2016 lúc 18:19

choán

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Huệ Thị Hồng Trần

4 tháng 8 2016 lúc 18:42

ng bai 1 thui

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Trịnh Thành Long K9A2 (...

9 tháng 7 2023 lúc 8:23

bài 4 : viết các biểu thức sau dưới dạng tích

a , 25 x mũ 2 -16

b , 16 a mũ 2 - 9 b mũ 2

c , 8 x mũ 3 + 1

d , 125 x mũ 3 + 27 y mũ 3

e , 8 x mũ 3 - 125

g , 27 x mũ 3 - y mũ 3

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Lớp 8 Toán Câu hỏi của OLM

Kiều Vũ Linh CTV

9 tháng 7 2023 lúc 8:32

a) 25x² - 16

= (5x)² - 4²

= (5x - 4)(5x + 4)

b) 16a² - 9b²

= (4a)² - (3b)²

= (4a - 3b)(4a + 3b)

c) 8x³ + 1

= (2x)³ + 1³

= (2x + 1)(4x² - 2x + 1)

d) 125x³ + 27y³

= (5x)³ + (3y)³

= (5x + 3y)(25x² - 15xy + 9y²)

e) 8x³ - 125

= (2x)³ - 5³

= (2x - 5)(4x² + 10x + 25)

g) 27x³ - y³

= (3x)³ - y³

= (3x - y)(9x² + 3xy + y²)

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Nguyễn Đức Trí

9 tháng 7 2023 lúc 8:33

a) \(25x^2-16=\left(5x-4\right)\left(5x+4\right)\)

b) \(16a^2-9b^2=\left(4a-3b\right)\left(4a+3b\right)\)

c) \(8x^3+1=\left(2x+1\right)\left(4x^2-2x+1\right)\)

d) \(125x^3+27y^3=\left(5x+3y\right)\left(25x^2-15xy+9y^2\right)\)

e) \(8x^3-125=\left(2x-5\right)\left(4x^2-10x+25\right)\)

g) \(27x^3-y^3=\left(3x-y\right)\left(9x^2+3xy+y^2\right)\)

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Đoàn Khôi Nguyên

9 tháng 7 2023 lúc 8:39

tao phá olm đêy nè:

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[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉ύ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉β҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉φ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉ύ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉υ҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉β҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉η҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉[҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̅҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉̲҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉-҉]҉[҉̅҉̲҉҉҉]҉[҉̅҉̲҉]҉]҉[҉̅҉̲҉҉҉]҉

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Music is my life

18 tháng 1 2016 lúc 8:42

Bài 1 : Tính hợp lý ( nếu có thể )
a) [(-27) + 43]+(-7.3)
b)-(-526 ) + ( -350)+(-150)+74
c)-25.27+25.21-49.25
Bài 2 : Tìm số nguyên x biết
a)2x+11=3(x-9)
b)2x^2-3=29
c)|x-3|+13=25
BÀi 4 : Cho biểu thức : A= (-a+b-c)-(-a-b-c)
Rút gọn A
Bài 5 : Tính tổng sau :
a) 1-2+3-4+5-6+...+99-100
b) ( -2)+4+(-6)+8+...+(-2014)+2016
Bài 6 : Tìm tất cả các số nguyên a biết
6a+1 chia hết chp 2a-1

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Lớp 5 Toán Câu hỏi của OLM

Bùi Danh Nghệ

18 tháng 1 2016 lúc 8:55

tic cho mình hết âm nhé

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Ngọc Nguyễn Ánh

9 tháng 9 2016 lúc 15:49

Bài 1: chứng minh rằng: x^2 - 2x +2 0 với mọi xBài 2 : tìm số a để đa thức x^3 - 3x^2 +5x +a chia hết cho x-2Bài 3: Tính nhanh các gt của biểu thức sau: a) 53^2 + 47^2 +94.53b) 50^2 - 49^2 + 48^2 - 47^2 + 2^2 - 1^2c) 57^2 + 26.87 + 13^2Bài 4: phân tích các đa thức sau thành nhân tử: a) x^2 -5x+4b) x^2 - y^2 +2x +1c) x^2 - y^2 - 5x +5yd) 5x^3 - 5x^2y - 10x + 10xye) 2x^2 - 5x +7Bài 5: phân tích các đa thức sau thành nhân tửa) x^3 - 3x^2 +1 -3xb) 3x^2 -6xy + 3y^2 -12z^2c) x^2 - 3x +2Bài 6: Rút gọ...

Đọc tiếp

Bài 1: chứng minh rằng: x^2 - 2x +2 >0 với mọi x

Bài 2 : tìm số a để đa thức x^3 - 3x^2 +5x +a chia hết cho x-2

Bài 3: Tính nhanh các gt của biểu thức sau:

a) 53^2 + 47^2 +94.53

b) 50^2 - 49^2 + 48^2 - 47^2 + 2^2 - 1^2

c) 57^2 + 26.87 + 13^2

Bài 4: phân tích các đa thức sau thành nhân tử:

a) x^2 -5x+4

b) x^2 - y^2 +2x +1

c) x^2 - y^2 - 5x +5y

d) 5x^3 - 5x^2y - 10x + 10xy

e) 2x^2 - 5x +7

Bài 5: phân tích các đa thức sau thành nhân tử

a) x^3 - 3x^2 +1 -3x

b) 3x^2 -6xy + 3y^2 -12z^2

c) x^2 - 3x +2

Bài 6: Rút gọn các biểu thức sau

a) (2x+1)^2 + 2(4x^2-a) + ( 2x-1)^2

b) (x^2 - 1)(x+2) - (x-2)(x^2 +2x +4)

giúp mình giải hết với ạ.mk cảm ơn nhiều

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Lớp 8 Toán Ôn tập toán 8

Bùi Hà Chi

9 tháng 9 2016 lúc 15:58

Dễ nhưng mà dài chết người

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A Lan

10 tháng 12 2016 lúc 21:24

Bài 1:

Ta có: \(x^2-2x+2=x^2-2x+1+1\)

\(=\left(x^2-2x+1\right)+1\)

\(=\left(x-1\right)^2+1\)

Ta thấy rằng: \(\left(x-1\right)^2\ge0\) ( Với mọi \(x\in Z\) )

mà 1 > 0

=> \(\left(x-1\right)^2+1\ge0\)

<=> \(x^2-2x+1\ge0\)

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A Lan

10 tháng 12 2016 lúc 21:34

Bài 3:

a) 53^2 + 47^2 + 94.53

= 53^2 + 47^2 + 2.47.53

= ( 53 + 47 )^2

= 100^2

= 10000

b) 50^2 - 49^2 + 48^2 - 47^2 + 2^2 - 1^2

= ( 50^2 - 49^2 ) + ( 48^2 - 47^2 ) + ( 2^2 - 1^2 )

= (50+49).(50-49) + (48+47).(48-47) + (2+1).(2-1)

= 50 + 49 + 48 + 47 + 2 + 1

= (49 + 1) + (48 + 2) + 50 + 47

= 50 + 50 + 50 + 47

= 197

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Biện Bạch Ngọc

9 tháng 9 2016 lúc 15:48

Bài 1: chứng minh rằng: x^2 - 2x +2 0 với mọi xBài 2 : tìm số a để đa thức x^3 - 3x^2 +5x +a chia hết cho x-2Bài 3: Tính nhanh các gt của biểu thức sau: a) 53^2 + 47^2 +94.53b) 50^2 - 49^2 + 48^2 - 47^2 + 2^2 - 1^2c) 57^2 + 26.87 + 13^2Bài 4: phân tích các đa thức sau thành nhân tử: a) x^2 -5x+4b) x^2 - y^2 +2x +1c) x^2 - y^2 - 5x +5yd) 5x^3 - 5x^2y - 10x + 10xye) 2x^2 - 5x +7Bài 5: phân tích các đa thức sau thành nhân tửa) x^3 - 3x^2 +1 -3xb) 3x^2 -6xy + 3y^2 -12z^2c) x^2 - 3x +2Bài 6: Rút gọ...

Đọc tiếp

Bài 1: chứng minh rằng: x^2 - 2x +2 >0 với mọi x

Bài 2 : tìm số a để đa thức x^3 - 3x^2 +5x +a chia hết cho x-2

Bài 3: Tính nhanh các gt của biểu thức sau:

a) 53^2 + 47^2 +94.53

b) 50^2 - 49^2 + 48^2 - 47^2 + 2^2 - 1^2

c) 57^2 + 26.87 + 13^2

Bài 4: phân tích các đa thức sau thành nhân tử:

a) x^2 -5x+4

b) x^2 - y^2 +2x +1

c) x^2 - y^2 - 5x +5y

d) 5x^3 - 5x^2y - 10x + 10xy

e) 2x^2 - 5x +7

Bài 5: phân tích các đa thức sau thành nhân tử

a) x^3 - 3x^2 +1 -3x

b) 3x^2 -6xy + 3y^2 -12z^2

c) x^2 - 3x +2

Bài 6: Rút gọn các biểu thức sau

a) (2x+1)^2 + 2(4x^2-a) + ( 2x-1)^2

b) (x^2 - 1)(x+2) - (x-2)(x^2 +2x +4)

giúp mình giải hết với ạ.mk cảm ơn nhiều

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Lớp 8 Toán Ôn tập toán 8

Lê Khánh Vy

10 tháng 9 2016 lúc 21:44

Bài 1 :

x²-2x+2>0 với mọi x

=x²-2.x.1/4+1/16+31/16

=(x-1/4)² + 31/16

Vì (x-1/4)² \(\ge\) 0 nên (x-1/4)² + 31/16 \(\ge\) 0 với mọi x (đfcm)

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Nguyễn Đăng Khoa

26 tháng 10 2016 lúc 14:52

các bạn giúp tôi các bài toán này được không cảm ơn nhiều

Câu 1:Phân tích các đa thức sau thành nhân tử

a)x^2+2x-4z^2+1

b)4x^2+4xy-16+y^2

c) a^2-b^2-4a+4

d)4x^2y^2-(x^2+y^2)^2

e)2a^3-54b^3

f)x^2+2x-3

Câu 2: Rút gọn các biểu thức sau:

a)(3x+2).(x-5)-2x(x-3)

b)(2x-3)^2+(2x+1).(2x-1)

c)(x+3)(x-3)+x.(2-x)

d)(2x+1)^2+(x+1)^2-2(2x+1).(x+1)

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Lớp 8 Toán Câu hỏi của OLM

Phương Thúy Nguyễn

26 tháng 7 2015 lúc 20:29

Viết các biểu thức sau dưới dạng đa thức thu gọn

a) (3ux - x + 1/4).4u³x

b) (ax² + bx + c).2a^2x

c) 5a²b³x.(2/5. ax² - x + 1/b²) ( b khác 0)

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Lớp 7 Toán Câu hỏi của OLM

Câu hỏi

Khoá học trên OLM (olm.vn)